18x^2+25x+8=0

Solution for 18x^2+25x+8=0 equation:

18x^2+25x+8=0

a = 18; b = 25; c = +8;
Δ = b2-4ac
Δ = 252-4·18·8
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-7}{2*18}=\frac{-32}{36}
=-8/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+7}{2*18}=\frac{-18}{36}
=-1/2
$